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소감 ¶
{{| 2005/05/11 Accepted 0:00.002 64 |}}
평이한 문제. 이산수학이 생각난다. if...else 구문을 사용할때 모든 조건을 프로그램에서 포함하는지 주의깊게 코딩해야 한다.
코드 ¶
~cpp // no10004 - Bicoloring #include <iostream> using namespace std; #define RED 1 #define BLACK 2 #define MAX_VERTEX 200 bool input(int edge[][2], int * nVertex, int * nInputLine); bool isBicolorale(int edge[][2], int nVertex, int nInputLine); bool paintColor(int count, int vertex, int * color); int main() { int nVertex; int nInputLine; int edge[MAX_VERTEX][2]; while (input(edge, &nVertex, &nInputLine)) { if (isBicolorale(edge, nVertex, nInputLine)) cout << "BICOLORABLE.\n"; else cout << "NOT BICOLORABLE.\n"; } return 0; } bool isBicolorale(int edge[][2], int nVertex, int nInputLine) { bool check[MAX_VERTEX] = {0,}; // using node = nInputLine int color[MAX_VERTEX] = {0,}; // using vertex = nVertex color[0] = BLACK; // 0's Node = BLACK int count = 0; // count = vertex number while (count != nVertex) { for (int i = 0; i < nInputLine; i++) { if (check[i] == false) // check 되지 않은 라인 { if (count == edge[i][0]) // { if (paintColor(count, edge[i][1], color) == false) return false; } if (count == edge[i][1]) { if (paintColor(count, edge[i][0], color) == false) return false; } } } count++; } return true; } bool paintColor(int count, int vertex, int * color) { if (color[count] == BLACK) { if (color[vertex] == BLACK) return false; color[vertex] = RED; } else { if (color[vertex] == RED) return false; color[vertex] = BLACK; } return true; } bool input(int edge[][2], int * nVertex, int * nInputLine) { cin >> *nVertex; if (*nVertex == 0) return false; cin >> *nInputLine; for (int i = 0; i < *nInputLine; i++) cin >> edge[i][0] >> edge[i][1]; return true; }