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Ant OnAChessboard/문보창

소감

2006-02-01 Accepted 0.000 Minimum
어느정도의 규칙(?)만 파악한다면 O(1)만에 구할 수 있다.

코드

~cpp
// 10161 - Ant on a Chessboard
#include <iostream>
using namespace std;
#include <cmath>

static int t;

inline void show(const int i, const int j)
{
	cout << i << ' ' << j << endl;
}

void show_typeA(const int x, const int y)
{
	if (t - x * x <= x)
		show(t - x * x, x + 1);
	else
		show(y, y * y - t + 1);
}

void show_typeB(const int y, const int x)
{
	if (x * x - t <= y)
		show(x * x - t + 1, y + 1);
	else
		show(y + 1, t - y * y);
}

void show_typeS(const int x)
{
	if (x & 0x1)
		show(1, x);
	else
		show(x, 1);
}

void process()
{
	int x = floor(sqrt(t));
	if (x == sqrt(t))
		show_typeS(x);
	else if (x & 0x1)
		show_typeA(x, x + 1);	
	else
		show_typeB(x, x + 1);
}

int main()
{
	while (cin >> t && t != 0)
		process();
	return 0;
}
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