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해제 ¶
~cpp
#include<iostream>
using namespace std;
int main()
{
char Str[100000]={0};
cin >> Str;
int a;
int count=0;
int i=0;
int b;
int c=0;
while(true)
{
b=Str[count];
if (b==0)
break;
while(true)
{
b= Str[count];
if( b<'0' || '9'<b)
break;
if('0'<= b && '9'>=b)
c = c*10 + (b-'0');
count++;
}
a= c;
for (i=0; i<a; i++)
{
cout << Str[count];
}
count =count+1;
c=0;
}
cout <<"\n";
return 0;
}
DPCM압축 ¶
~cpp
#include<iostream>
using namespace std;
int main()
{
char Str[20]={0};
cin >> Str;
char FM;
FM= Str[0];
cout << FM;
int i=0;
while(true)
{
if(Str[i]==0)
break;
cout << Str[i]-FM;
i++;
}
cout <<"\n";
return 0;
}
DPCM 해제 ¶
~cpp
#include<iostream>
using namespace std;
int main()
{
char Str[20]={0};
cin >> Str;
char FM;
FM= Str[0];
int i=1;
while(true)
{
if(Str[i]==0)
break;
if(Str[i]=='-')
{
cout << (char) (FM-(Str[i+1]-'0'));
i++;
}
else
cout << (char) (Str[i]-'0'+FM);
i++;
}
return 0;
}
ADPCM 압축 ¶
~cpp
#include<iostream>
using namespace std;
int main()
{
char Str[20]={0};
cin >> Str;
char FM;
FM= Str[0];
cout << FM;
int i=0;
while(true)
{
if(Str[i]==0)
break;
if(Str[i]-FM>=10)
{
FM=Str[i];
cout << FM;
}
cout << Str[i]-FM;
i++;
}
return 0;
}
ADPCM 해제 ¶
~cpp
#include<iostream>
using namespace std;
int main()
{
char Str[20]={0};
cin >> Str;
char FM;
FM= Str[0];
int i=1;
while(true)
{
if(Str[i]==0)
break;
if(Str[i]=='-')
{
cout << (char) (FM-(Str[i+1]-'0'));
i++;
}
else if('A'<=Str[i] && Str[i]<='Z')
FM=Str[i];
else
cout << (char) (Str[i]-'0'+FM);
i++;
}
return 0;
}