WERTYU/1002

~cpp 
def left(c):
    if c == ' ': return ' '
    dicStrs= """`1234567890-=QWERTYUIOP[]\ASDFGHJKL;'ZXCVBNM,./"""
    return dicStrs[dicStrs.find(c)-1]

def wertyu(s):
    return ''.join([left(each) for each in list(s)])

def testOne():
    r"""
    ��������� ������들로는..
    ���단 무���가 ���당 ���릭������ 대������ ��������� 변���������는 것��� ������면 ���겠고
    >>> left("O")
    'I'
    >>> left(" ")
    ' '
    >>> left("S")
    'A'

    만��� ���것��� ���다고 ���다면.. 각 char 단������ 결과를 그냥 그대로 ��������리면 될 듯 ���다.

    >>> [left(each) for each in list("O S")]
    ['I', ' ', 'A']

    ��� 부����� 대������는 ������로 빼낼 것���고, ���를 ������링��� ���면 ������ ���로덕���.
    >>> wertyu("O S, GOMR YPFSU/")
    'I AM FINE TODAY.'
    """

def main():
    print wertyu(raw_input())

if __name__=="__main__":
    import doctest
    doctest.testmod()