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Reverse And Add/이동현

소스


~cpp 
def reverse(n, count):
	if(count ==1000):
		print "회문을 찾을 수 없는수?"
	if(str(n) != str(n)[::-1]):
		reverse(n+int(str(n)[::-1]), count+1)
	else:
		print n

~cpp 
reverse(195,0)
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