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  • SpiralArray/영동 . . . . 22 matches
         const int MAX_X=5;
         const int MAX_Y=5;
         void showBoard(int aBoard[][MAX_X]);//배열을 보여준다
         void setEmptyBoard(int aBoard[][MAX_X]);//배열 초기화
         bool needToChangeDirection(Mover * aMover, int aBoard[][MAX_X]);//방향을 바꿀 필요가 있는지 검사
         void checkAtBoard(int aBoard[][MAX_X], Mover * aMover, int * aNumber);//이동 결과를 배열에 표시
          int board[MAX_X][MAX_Y];//배열
         void showBoard(int aBoard[][MAX_X])
          for(int i=0;i<MAX_Y;i++)
          for(int j=0;j<MAX_X;j++)
         void setEmptyBoard(int aBoard[][MAX_X])
          for(int i=0;i<MAX_Y;i++)
          for(int j=0;j<MAX_X;j++)
          if(endCount<MAX_X*MAX_Y)
         bool needToChangeDirection(Mover * aMover, int aBoard[][MAX_X])
          if(aMover->currentX+MOVE_X[aMover->currentDirection]>=MAX_X)
          return true;//X방향으로 배열을 빠져나갈 경우(MAX이상)
          if(aMover->currentY+MOVE_Y[aMover->currentDirection]>=MAX_Y)
          return true;//Y방향으로 배열을 빠져나갈 경우(MAX이상)
         void checkAtBoard(int aBoard[][MAX_X], Mover * aMover, int * aNumber)
  • PowerOfCryptography/조현태 . . . . 21 matches
          두번째 소스.. 숫자가 커도 저장하고 연산할 수 있을...듯 하다..;;ㅁ;; ㅎㅎㅎ MAX_LONG의 값을 10으로 줄이고 테스트를 해서 2개 이상의 경우에도 돌아가는 것은 알겠는데... 3번째 4번째 예제의 수가 원체 커야지 말이다. 연산의 결과가 좀처럼 안나온다. 곱하기 루틴에서 계속 더하고 있는듯..;;ㅁ;;
          unsigned __int64 min_answer=1, max_answer=mokpyo+1;
          while (min_answer+1!=max_answer)
          unsigned __int64 temp_target=(min_answer+max_answer)/2;
          max_answer=temp_target;
         const unsigned __int64 MAX_LONG=1000000000000000000;
          prv->number_input(number/MAX_LONG);
          number%=MAX_LONG;
          prv=new save_number(number/MAX_LONG,this);
          number%=MAX_LONG;
          prv->plus_number_unsigned(number/MAX_LONG);
          number%=MAX_LONG;
          prv=new save_number(number/MAX_LONG,this);
          number%=MAX_LONG;
          if (number>=MAX_LONG)
          return MAX_LONG;
          if (number>=MAX_LONG)
          if (MAX_LONG==get_number)
          if (MAX_LONG==get_number)
          while (this_number!=MAX_LONG)
  • 3N+1Problem/Leonardong . . . . 19 matches
          def getMaximumCycleLength(self, aFrom, aTo):
          max = 0
          if max < cycleLength:
          max = cycleLength
          return max
          print self.getMaximumCycleLength(numFrom, numTo)
          def testGetMaximumCycleLength(self):
          self.assertEquals( 1, self.runner.getMaximumCycleLength( 1, 1 ) )
          self.assertEquals( 20, self.runner.getMaximumCycleLength( 1, 10 ) )
          self.assertEquals( 125, self.runner.getMaximumCycleLength( 100, 200 ) )
          self.assertEquals( 89, self.runner.getMaximumCycleLength( 201, 210 ) )
          self.assertEquals( 174, self.runner.getMaximumCycleLength( 900, 1000) )
         MAXIMUM = 10000
          def getMaximumCycleLen(self, aFrom, aTo):
          maximum = 0
          if self.getCycleLen(i) > maximum:
          maximum = self.getCycleLen(i)
          self.cycleLens[i] = maximum
          return maximum
          print self.getMaximumCycleLen(numFrom, numTo)
  • 큰수찾아저장하기/조현태 . . . . 16 matches
         const int MAX_GARO=4;
         const int MAX_SAERO=4;
          int number[MAX_SAERO][MAX_GARO]={0,};
          for (register int i=0; i<MAX_SAERO-1; ++i)
          for (register int j=0; j<MAX_GARO-1; ++j)
          if (number[i][j]>number[i][MAX_GARO-1])
          number[i][MAX_GARO-1]=number[i][j];
          if (number[i][j]>number[MAX_SAERO-1][j])
          number[MAX_SAERO-1][j]=number[i][j];
          if (number[i][j]>number[MAX_SAERO-1][MAX_GARO-1])
          number[MAX_SAERO-1][MAX_GARO-1]=number[i][j];
          for (register int i=0; i<MAX_SAERO; ++i)
          for (register int j=0; j<MAX_GARO; ++j)
  • AdventuresInMoving:PartIV/문보창 . . . . 15 matches
         #define MAX_OIL 200
         #define MAX_SIZE 101
         #define MAX_NUM 1000000000
         static Station station[MAX_SIZE]; /* 주유소 정보 */
         static int d[2][MAX_OIL+1]; /* 다이나믹 테이블 */
          for (int j = 0; j <= MAX_OIL; j++)
          d[1][j] = MAX_NUM;
          for (j = 0; j <= MAX_OIL; j++)
          min = MAX_NUM;
          for (k = 0; k <= MAX_OIL; k++)
          if (k - getDistance(i) < 0 || d[(i-1)%2][k] >= MAX_NUM || j < k - getDistance(i))
          min = MAX_NUM;
          for (j = 100; j <= MAX_OIL; j++)
          if (d[numStation%2][j] < MAX_NUM && d[numStation%2][j] < min && j - (totalLength - station[numStation].length) >= 100)
          if (min >= MAX_NUM)
  • VonNeumannAirport/Leonardong . . . . 14 matches
          for origin in range( 1, MAX+1 ):
          for dest in range( 1, MAX+1 ):
         MAX = 25
          self.distMatrix = DistanceMatrix(MAX)
          self.traffic = TrafficMatrix(MAX)
          self.distMatrix.construct( origins = range(1,MAX+1),
          destinations= range(1,MAX+1) )
          for i in range( 1, MAX+1 ):
          self.distMatrix.construct( origins = range(1,MAX+1),
          destinations= range(MAX,0,-1) )
          self.assertEquals( 1, self.distMatrix.getDistance( 1, MAX ) )
          self.assertEquals( MAX, self.distMatrix.getDistance( 1, 1 ) )
          self.assertEquals( 1, self.distMatrix.getDistance( MAX/2+1,# middle
          MAX/2+1 ) )
  • IsBiggerSmarter?/문보창 . . . . 13 matches
         const int MAX_ELEPHANT = 1100;
          Elephant elephant[MAX_ELEPHANT];
          int max_count = 0;
          result.reserve(MAX_ELEPHANT);
          v_temp.reserve(MAX_ELEPHANT);
          if (count > max_count)
          max_count = count;
          cout << max_count << endl;
          for (i = 0; i < max_count; i++)
         const int MAX_ELEPHANT = 1010;
         Elephant elephant_weight[MAX_ELEPHANT];
         Elephant elephant_IQ[MAX_ELEPHANT];
         int lcs_length(unsigned char t[][MAX_ELEPHANT]);
         void print_lcs(int i, int j, unsigned char t[][MAX_ELEPHANT]);
          unsigned char table[MAX_ELEPHANT][MAX_ELEPHANT];
         int lcs_length(unsigned char t[][MAX_ELEPHANT])
         void print_lcs(int i, int j, unsigned char t[][MAX_ELEPHANT])
  • OurMajorLangIsCAndCPlusPlus/float.h . . . . 13 matches
         ||FLT_MAX ||float형으로 표현할 수 있는 가장 큰 floating point 값 ||3.402823466e+38F ||
         ||DBL_MAX ||double형으로 표현할 수 있는 가장 큰 floating point 값 ||1.7976931348623158e+308 ||
         ||LDBL_MAX ||long double형으로 표현할 수 있는 가장 큰 floating point 값 ||1.7976931348623158e+308 ||
         ||FLT_MAX_10_EXP ||float형으로 표현할 수 있는 가장 큰 floating point의 10의 지수값 ||38 ||
         ||DBL_MAX_10_EXP ||double형으로 표현할 수 있는 가장 큰 floating point의 10의 지수값 ||308 ||
         ||LDBL_MAX_10_EXP ||long double형으로 표현할 수 있는 가장 큰 floating point의 10의 지수값 ||308 ||
         ||FLT_MAX_EXP ||float형으로 표현할 수 있는 가장 큰 floating point의 2의 지수값 ||128 ||
         ||DBL_MAX_EXP ||double형으로 표현할 수 있는 가장 큰 floating point의 2의 지수값 ||1024 ||
         ||LDBL_MAX_EXP ||long double형으로 표현할 수 있는 가장 큰 floating point의 2의 지수값 ||1024 ||
         '''FLT_MAX'''
         이 매크로의 값은 float형이 표현할 수 있는 최대 수를 의미한다. 이것은 적어도 1E+37이 된다. 값 자체도 float형을 갖는다. 표현 가능한 가장 작은 수는 -FLT_MAX가 된다.
         '''FLT_MAX_EXP'''
         '''FLT_MAX_10_EXP'''
  • 기본데이터베이스/조현태 . . . . 13 matches
         const int MAX_DATA_SIZE=100;
         const int MAX_MENU=8;
         const char menu[MAX_MENU][20]={"insert","modify","delete","undelete","search","list","quit","?"};
         const int MAX_BLOCK_SIZE=256;
         char datas[MAX_DATA_SIZE+1][HANG_MOK][MAX_BLOCK_SIZE];
          void (*functions[MAX_MENU])(void)={function_insert,function_modify,function_delete,function_undelete,function_search,function_list,function_quit,function_help};
          for (register int i=0; i<MAX_MENU; ++i)
          if (MAX_DATA_SIZE==how_many_data)
          strcpy(datas[MAX_DATA_SIZE][i],datas[target][i]);
          strcpy(datas[prv_del][i],datas[MAX_DATA_SIZE][i]);
          for (register int i=0; i<MAX_MENU; ++i)
          char temp_data[MAX_BLOCK_SIZE];
  • 손동일 . . . . 13 matches
         const int Max = 11 ;
         int Vertex[Max][Max] =
         int n = Max;
         int between[Max];
         int check[Max];
         void shortpath(int Vertex[Max][Max],int between[Max], int n, int check[Max]);
         int choose(int between[Max],int n,int check[Max]);
          int between[Max];
         void shortpath(int Vertex[Max][Max],int between[Max], int n, int check[Max])
         int choose(int between[Max],int n,int check[Max])
          minimum = Max;
         const int MAX = 11;
          int neighbor[MAX][2];
          sVertice vertices[MAX] =
          for (int i = 0 ; i < MAX ; i++)
          vertices[i].len_from_start = INT_MAX;
          for (i = 0 ; i < MAX ; i++)
          for (int j = 0 ; j < MAX ; j++)
          if (vertices[i].len_from_start == INT_MAX)
          for (i = 0 ; i < MAX ; i++)
  • ACM_ICPC/PrepareAsiaRegionalContest . . . . 12 matches
          const int MAX = 1001;
          static int workspace[MAX][MAX];
          for ( int i = 0 ; i < MAX ; i++ )
          for ( int j = 0 ; j < MAX ; j++ )
          int max = 0;
          for ( x = 0 ; x < MAX-SQUARE_SIZE ; x++ ){
          for ( y = 0 ; y < MAX-SQUARE_SIZE ; y++ ){
          if ( count > max )
          max = count;
          cout << " " << max << endl;
         const int MAX = 4;
         const int INT_MAX = 20000000;
          GameEngine(){ minimum = INT_MAX; }
          else if ( count < MAX )
          if ( minimum == INT_MAX )
  • 방울뱀스터디/만두4개 . . . . 12 matches
         MAX_WIDTH, MAX_HEIGHT = 314, 314
          if dir == 'Right'and'Space' and x <= MAX_WIDTH-GAP-10 :
          elif dir == 'Down' and y <= MAX_HEIGHT - GAP - 10:
          #canvas.create_rectangle(GAP, GAP, MAX_WIDTH - GAP, MAX_HEIGHT - GAP)
          #if dir == 'Right' and x < MAX_WIDTH - GAP - 10:
          #elif dir == 'Down' and y < MAX_HEIGHT - GAP - 10:
          canvas = Canvas(root, width = MAX_WIDTH, height = MAX_HEIGHT, bg='white')
          canvas.create_rectangle(GAP, GAP, MAX_WIDTH - GAP, MAX_HEIGHT - GAP)
  • Marbles/신재동 . . . . 10 matches
         const int MAX_NUMBER = 1000;
         unsigned int marbles[MAX_NUMBER] = {0,};
         unsigned int c1[MAX_NUMBER] = {0,};
         unsigned int n1[MAX_NUMBER] = {0,};
         unsigned int c2[MAX_NUMBER] = {0,};
         unsigned int n2[MAX_NUMBER] = {0,};
         unsigned int m1[MAX_NUMBER] = {MAX_NUMBER,};
         unsigned int m2[MAX_NUMBER] = {MAX_NUMBER,};
          int maxX = marbles[i] / n1[i];
          int maxY = marbles[i] / n2[i];
          for(int x = 0; x < maxX; x++)
          for(int y = 0; y < maxY; y++)
  • ErdosNumbers/문보창 . . . . 9 matches
         const int MAX_STR = 20;
         const int MAX_ERNUM = 100;
          char name[MAX_STR];
         pNode head[MAX_ERNUM];
         bool make_map(char name[][MAX_STR], int num);
          for (int i = 0; i < MAX_ERNUM; i++)
          for (int i = 1; i < MAX_ERNUM; i++)
          char name[10][MAX_STR];
         bool make_map(char name[][MAX_STR], int num)
  • C++스터디_2005여름/학점계산프로그램/정수민 . . . . 8 matches
         #define MAX_STUDENT 121
          students = new Student[MAX_STUDENT];
          for (int i=1;i<MAX_STUDENT;i++) {
          int num=MAX_STUDENT/10;
          for (i=1;i < MAX_STUDENT;i++)
          for (i=1;i < MAX_STUDENT;i++)
          for (int i=1;i<MAX_STUDENT;i++)
          for (int i=1;i<MAX_STUDENT;i++)
  • ContestScoreBoard/허아영 . . . . 8 matches
         #define MAX_OF_TEAM_NUM 100
         #define MAX_OF_Q 9
          int team_data[MAX_OF_TEAM_NUM+1][MAX_OF_Q+1]; // 0번째 배열은 시간 벌점 다음부터는
          int temp_team_num, q_num, q_index[MAX_OF_TEAM_NUM]; // 문제 푼 index
          for(i = 0; i <= MAX_OF_TEAM_NUM; i++)
          for(int j = 1; j <= MAX_OF_Q; j++)
          for(i = 1; i <= MAX_OF_TEAM_NUM; i++)
  • EcologicalBinPacking/강희경 . . . . 8 matches
          int MAX = 0;
          if(noMove[i] > MAX)
          MAX = noMove[i];
          movedBottle -= MAX;
          int MAX = 0;
          if(pNoMove[i] > MAX)
          MAX = pNoMove[i];
          aSlots[9] -= MAX;
  • HowManyPiecesOfLand?/문보창 . . . . 8 matches
         #define MAXDIGITS 100
         #define MAX(a,b) (((a) > (b)) ? (a) : (b))
          char digit[MAXDIGITS];
          for (i = lastdigit + 1; i < MAXDIGITS; i++)
          for (i = 0; i < MAXDIGITS; i++)
          char temp[MAXDIGITS];
          ret.lastdigit = MAX(a.lastdigit, b.lastdigit) + 1;
          ret.lastdigit = MAX(a.lastdigit,b.lastdigit);
  • OurMajorLangIsCAndCPlusPlus/locale.h . . . . 8 matches
         char frac_digits; CHAR_MAX LC_MONETARY
         char int_frac_digits; CHAR_MAX LC_MONETARY
         char n_cs_precedes; CHAR_MAX LC_MONETARY
         char n_sep_by_space; CHAR_MAX LC_MONETARY
         char n_sign_posn; CHAR_MAX LC_MONETARY
         char p_cs_precedes; CHAR_MAX LC_MONETARY
         char p_sep_by_space; CHAR_MAX LC_MONETARY
         char p_sign_posn; CHAR_MAX LC_MONETARY
  • VendingMachine/세연/1002 . . . . 8 matches
         const int DRINKNAME_MAXLENGTH = 255;
          max_num = TOTAL_DRINK_TYPE;
          char drinkNames[TOTAL_DRINK_TYPE][DRINKNAME_MAXLENGTH] = {"coke", "juice", "tea", "cofee", "milk"};
          for (int i=0; i<max_num; i++) {
         const int DRINKNAME_MAXLENGTH = 255;
          char name[DRINKNAME_MAXLENGTH];
          int max_num;
          max_num = TOTAL_DRINK_TYPE;
          char drinkNames[TOTAL_DRINK_TYPE][DRINKNAME_MAXLENGTH] = {"coke", "juice", "tea", "cofee", "milk"};
          for (int i=0; i<max_num; i++) {
          for(int i = 0 ; i < max_num ; i++)
          for(int i = 0 ; i < max_num ; i++)
          for(i = 0 ; i < max_num ; i++)
          for(int drinkIndex = 0 ; drinkIndex < max_num ; drinkIndex++)
         const int DRINKNAME_MAXLENGTH = 255;
          char name[DRINKNAME_MAXLENGTH];
          int max_num;
          max_num = TOTAL_DRINK_TYPE;
          char drinkNames[TOTAL_DRINK_TYPE][DRINKNAME_MAXLENGTH] = {"coke", "juice", "tea", "cofee", "milk"};
          for (int i=0; i<max_num; i++) {
  • XOR삼각형/aekae . . . . 8 matches
         const int MAX = 8;
          int arr[MAX][MAX];
          for (int i=0; i<MAX; i++)
          for (j=1; j<MAX; j++)
          for (k=0; k<MAX; k++)
          for (j=0; j<MAX; j++)
          for (int h=j; h<MAX-1; h++)
  • 금고/문보창 . . . . 8 matches
         {{| max{ T(b, k), T(a, k-1) } + 1 |}} 이다.
         #define MAXN 500
         static int d[MAXN+1][MAXN+1];
          for (int i = 1; i <= MAXN; i++)
         int find_max_n(int k, int value)
          for (int i = 1; i <= MAXN; i++)
          while (t < MAXN)
          a = find_max_n(k - 1, value);
          for (int i = b + 1; i <= __min(t,MAXN); i++)
          for (int k = 2; k <= MAXN; k++)
  • 비행기게임/BasisSource . . . . 8 matches
         MAX_SHOTS = 5
          imageMax = 15
          maxShots = 1
          if self.imageCount <self.imageMax :
          imageMax = 4
          if self.imageCount <self.imageMax :
          imageMax = 5
          def __init__(self, life, imageMax, playerPosY):
          self.imageMax = imageMax
          if self.imageCount <self.imageMax and self.imageCount >= 0 :
          elif self.imageCount==self.imageMax-1:
         def DynamicEnemyAssign(enemyList, countOfEnemy, Enemy, life, imageMax, enemy_containers, Enemy_img, pathAndKinds, line, playerPosY):
          enemyList[countOfEnemy] = Enemy(life,imageMax, playerPosY)
         def DynamicItemAssign(itemList, countOfItem, Item, imageMax, item_containers, Item_img ,pos):
          MAX_ENEMY = 5
          MAX_ITEM = 6
          enemy_1 = range(MAX_ENEMY)
          enemy_2 = range(MAX_ENEMY)
          item_1 = range(MAX_ITEM)
          player.maxShots = player.maxShots + 1
  • AutomatedJudgeScript/문보창 . . . . 7 matches
         const int MAX = 100;
          char answer[MAX*MAX]; // 정답
          char answerDigit[MAX];
          char reply[MAX*MAX]; // 사용자 출력
          char replyDigit[MAX];
  • RandomWalk/동기 . . . . 7 matches
          int MAX=size-1;
          if (spawnY>=0 && spawnX<=MAX)
          if (spawnX<=MAX)
          if (spawnX<=MAX && spawnY<=MAX)
          if (spawnY<=MAX)
          if (spawnX>=0 && spawnY<=MAX)
  • TugOfWar/이승한 . . . . 7 matches
         const int MAX= 100;
         int maxToZero(int input[]); //가장큰수를 0로 바꾸어주는 함
          int weight[MAX] = {0};
          int outA[MAX] = {0};
          int outB[MAX] = {0};
          int maxInInput = 0;
          for(int cycle=0; cycle < MAX; cycle++){
          maxInInput = maxToZero( weight);
          if( teamA + maxInInput == aver ){
          teamA += maxInInput;
          }else if( teamB + maxInInput == aver ){
          teamB += maxInInput;
          teamA += maxInInput;
          teamB += maxInInput;;
         int maxToZero(int * weight){
          int max = 0;
          int maxsIndex = 0;
          for(int cycle=0; cycle < MAX; cycle++){
          if(max < weight[cycle]){
          max = weight[cycle];
  • 미로찾기/황재선허아영 . . . . 7 matches
         #define MAX 7
         int board[MAX][MAX];
          for(i = 0; i < MAX; i++)
          for (j = 0; j < MAX; j++)
          for(i = 0; i < MAX; i++)
          for (j = 0; j < MAX; j++)
  • CuttingSticks/문보창 . . . . 6 matches
         #define MAX_CUT 53
         #define MAX_NUM 0x7fffffff
         static int cut[MAX_CUT];
         static int d[MAX_CUT][MAX_CUT];
          min = MAX_NUM;
  • MagicSquare/동기 . . . . 6 matches
          int MAX = k-1;
          y=MAX;
          if (x>MAX)
          if (newy>MAX)
          for (int p=0;p<=MAX;p++)
          for (int l=0;l<=MAX;l++)
  • OurMajorLangIsCAndCPlusPlus/stdlib.h . . . . 6 matches
         || RAND_MAX || 랜덤 함수에 의해서 리턴되는 최대 값 (적어도 32, 767) ||
         || MB_CUR_MAX || 현재 사용 중인 로케일에서 멀티바이트 문자의 최대 길이 ||
         || int rand(void); || 0부터 RAND_MAX까지의 범위사이의 난수 리턴||
         #include <stdlib.h> /* For _MAX_PATH definition */
          string = malloc( _MAX_PATH );
          // string = (char *)malloc( _MAX_PATH );
  • RandomWalk2/상규 . . . . 6 matches
         #define MAX_JOURNEY 1024 // 최대 여정 수
         int walk(int m, int n, int starti, int startj, char journey[MAX_JOURNEY], int **board);
          char journey[MAX_JOURNEY];
          char buffer[MAX_JOURNEY];
          cin.getline(buffer,MAX_JOURNEY);
         int walk(int m, int n, int starti, int startj, char journey[MAX_JOURNEY], int **board)
  • SmithNumbers/신재동 . . . . 6 matches
         const int MAX_TEST = 100;
         const int MAX_PRIME_NUMBER = 100000;
         int MAIN_PRIME_NUMBER[MAX_PRIME_NUMBER] = {0,};
         int smithNumbers[MAX_TEST] = {0,};
          for (int i = 3; primeCount < MAX_PRIME_NUMBER; i += 2)
          for(int i = 0; i < MAX_PRIME_NUMBER; i++)
  • TheJavaMan/스네이크바이트 . . . . 6 matches
          public int MAX = 20;
          public int[][] board = new int [MAX][];
          for(int i=0; i<MAX; i++)
          board[i] = new int[MAX];
          for(int i=0; i<MAX; i++)
          for(int j=0; j<MAX; j++)
  • TugOfWar/문보창 . . . . 6 matches
         const int MAX_CASE = 100;
         const int MAX = 100;
          int weight[MAX];
          int left[MAX/2];
          int right[MAX/2];
          TugWar tugwar[MAX_CASE];
  • WeightsAndMeasures/문보창 . . . . 6 matches
         #define MAX_SIZE 5608
         #define MAX_WEIGHT 10000000
          int dynamic[2][MAX_SIZE];
          dynamic[1][i] = MAX_WEIGHT;
          if (dynamic[numT%2][i] < MAX_WEIGHT)
          Turtle turtle[MAX_SIZE];
  • 몸짱프로젝트/InfixToPostfix . . . . 6 matches
         const int MAX = 10;
         Element stack[MAX];
          return (top < MAX - 1 ? false : true);
          if ( *top < MAX - 1 )
          stack[MAX-1].op.token = 'e';
          stack[MAX-1].op.precedence = 100;*/
  • 빵페이지/도형그리기 . . . . 6 matches
         #define MAX 21
          char odd[MAX],even[MAX],format[20];
          printf("plz input asterisk number(below %d):",MAX);
          if( num > MAX ) exit(0);
          memset(odd,0,MAX);
  • 5인용C++스터디/클래스상속 . . . . 5 matches
         #define MAX_LEN 81
          char fname[MAX_LEN];
          char lname[MAX_LEN];
          char full[MAX_LEN+MAX_LEN];
  • C 스터디_2005여름/학점계산프로그램/김태훈김상섭 . . . . 5 matches
          MAX_SUB = 4;
          avg /= MAX_SUB;
          int MAX_SUB;
         const int MAX_SUB = 4;
          for(int i = 0; i < MAX_SUB; i++)
  • HardcoreCppStudy/첫숙제/Overloading/김아영 . . . . 5 matches
         const int MAX = 20;
          int board[MAX][MAX]={0,};
          char direction[MAX];
          for(int D=0;D<MAX;D++)
  • 새싹교실/2011/무전취식/레벨10 . . . . 5 matches
          int max = 0 ,min = 9999;
          int selectMin,selectMax;
          if (num[i]>max){
          max=num[i];
          selectMax = i;
          if (i==selectMin || i==selectMax) continue;
          max= 0;
          if (newnum[i]>max){
          max=newnum[i];
          // selectMax = i;
          if (max-min>=4) printf("KIN\n");
         #define MAX_LINESTR 200
         #define MAX_WORDLENGTH 200
         #define MAX_LINE 100
          char line_str[MAX_LINE][MAX_LINESTR];
  • AdventuresInMoving:PartIV/김상섭 . . . . 4 matches
         #define MAX_OIL 200
         #define MAX_SIZE 103
         #define MAX_NUM 1000000000
         static Station station[MAX_SIZE]; /* 주유소 정보 */
          int maxmin, maxminprice , now = 1, tank = 100, go = 100, search = 2, cost = 0;
          maxmin = 0;
          maxminprice = 1000000;
          maxmin = 0;
          if(maxminprice > station[search].price)
          maxmin = search;
          maxminprice = station[search].price;
          if(maxmin)
          if(station[maxmin].length - station[now].length >= tank)
          tank = go - station[maxmin].length + station[now].length;
          tank = tank - station[maxmin].length + station[now].length;
          now = maxmin;
  • LIB_3 . . . . 4 matches
          for (int count = 0;count<LIB_MAX_HEAP;count++) {
          free_tcb_ptr = LIB_MAX_HEAP;
          if ( priority < LIB_MIN_PRIORITY || priority > LIB_MAX_PRIORITY ) return; <--------- 우선순위가 지랄 같으면 그냥 끝낸다.
          for ( int i = 0; i < LIB_MAX_HEAP ; i++ ){
  • MineSweeper/문보창 . . . . 4 matches
         const int MAX = 100;
          int size[MAX]; // 행과 열만을 저장할 배열
          int mineSweep[MAX + 2][MAX + 2]; // 출력 할 지뢰밭 start point (1,1)
  • PrimaryArithmetic/황재선 . . . . 4 matches
         MAX = 9
          s1, s2 = n1.zfill(MAX), n2.zfill(MAX)
          for bit in range(MAX-1, -1, -1):
  • ReverseAndAdd/황재선 . . . . 4 matches
         MAX_VALUE = 4294967295
         MAX_COUNT = 1000
          if count >= MAX_COUNT or n > MAX_VALUE:
  • 김재현 . . . . 4 matches
         #define MAX 45 // 1-45
          unsigned char j,k,n, used[MAX];
          for (k=0; k < MAX; k++) //질문거리~(등호..)
          n=rand() % MAX;
  • 데블스캠프2011/다섯째날/HowToWriteCodeWell/김준석,서영주 . . . . 4 matches
          public int MAX_HEIGHT;
          public Elevator(int max_height, int min_height, int basic_height) {
          MAX_HEIGHT = max_height;
          if(i <= MAX_HEIGHT && i >= MIN_HEIGHT)
          public int getMaxHeight() {
          return MAX_HEIGHT;
          public void getMaxHeightTest(){
          assertEquals(el.getMaxHeight(), 20);
  • 숫자를한글로바꾸기/조현태 . . . . 4 matches
         const int MAX_LONG=5;//최대가 5자리 숫자이기때문.
         const int MAX_NUMBER=10000;//최대가 10000이기때문.
          int max_size_of_stack;
          max_size_of_stack=data_size;
          if (where_is_save != max_size_of_stack)
          stack print_number(MAX_LONG);
          while (input_number<0 || input_number>=MAX_NUMBER)
  • 이영호/미니프로젝트#1 . . . . 4 matches
         #define MSG_MAX 1024
          char msg[MSG_MAX];
          msg_len = recv(sockfd, msg, MSG_MAX-1, 0);
          fgets(msg, MSG_MAX, stdin);
  • Counting/문보창 . . . . 3 matches
         #define MAX_SIZE 1000
         static BigInteger Tn[MAX_SIZE+1];
          for (int i = 3; i <= MAX_SIZE; i++)
  • ErdosNumbers/차영권 . . . . 3 matches
         #define MAX_LENGTH 100
          char temp[MAX_LENGTH], *c;
          cin.getline(temp, MAX_LENGTH);
  • ImmediateDecodability/문보창 . . . . 3 matches
         const int MAX = 10;
          char code[MAX][11];
          for (i=0; i<MAX; i++)
  • Slurpys/문보창 . . . . 3 matches
         const int MAX_LEN = 61;
          char str[MAX_LEN];
          cin.getline(str, MAX_LEN, 'n');
  • XOR삼각형/임다찬 . . . . 3 matches
          const int MAX=50;
          int tri[MAX][MAX]={0,};
  • 이차함수그리기/조현태 . . . . 3 matches
         const int MAX_X=5;
         void make_image(int where_x, int where_y, float min_x, float max_x, float tab_x, float tab_y)
          int max_y=0;
          for (register float x=min_x; x<=max_x; x+=tab_x)
          if (max_y<function_x_to_y(x))
          max_y=function_x_to_y(x);
          for (register float x=min_x; x<=max_x; ++x)
          gotoxy(banollim(x-min_x+1+where_x),(where_y+max_y*tab_y));
          for (register float y=min_y; y<=max_y; ++y)
          gotoxy(banollim(-min_x+1+where_x),(where_y-banollim(y)*tab_y+max_y*tab_y));
          for (register float x=min_x; x<=max_x; x+=tab_x)
          gotoxy(banollim(x-min_x+1+where_x),(where_y-banollim(function_x_to_y(x))*tab_y+max_y*tab_y));
          make_image( 10 , 5 , MIN_X, MAX_X,TAB_X,TAB_Y);
          for (register int i=0; i<MAX_X-MIN_X+1;i+=1)
  • 파스칼삼각형/구자겸 . . . . 3 matches
         #define MAX 10
          int array[MAX][MAX]; // 배열
         def pascal(maxrow):
          arr = [ 0 for x in range(maxrow) for y in range(x+1) ]
          print ' '*(maxrow-stair),
          stair+=1; print ''; print ' '*(maxrow-stair),
  • 파스칼삼각형/임다찬 . . . . 3 matches
          const int MAX = 100;
          int pascalt[MAX+1][MAX]={0,};
  • ComputerNetworkClass/Report2006/PacketAnalyzer . . . . 2 matches
          char rcvbuf[MAX_IP_SIZE];
          wbuf.len = MAX_IP_SIZE;
  • Counting/하기웅 . . . . 2 matches
         #define MAX_NUM 1000
         BigInteger number[MAX_NUM+1];
  • EuclidProblem/차영권 . . . . 2 matches
         #define MAX 50
         }coefficient[MAX];
         int gcd(int max, int min);
         int gcd(int max, int min)
          if (max%min == 0)
          return gcd(min, max%min);
  • HanoiTowerTroublesAgain!/문보창 . . . . 2 matches
         #define MAX_SIZE 50
         static int stick[MAX_SIZE+1];
  • Slurpys/강인수 . . . . 2 matches
          if IsSlump(Copy(S, FPos+1, MAX_STR_LEN)) then
          if IsSlimp(Copy(S,1,i)) and IsSlump(Copy(S,i+1,MAX_STR_LEN)) then
  • The Trip/Celfin . . . . 2 matches
         #define MAX_STU 1000
         double student[MAX_STU+1];
  • TheTrip/문보창 . . . . 2 matches
         const int MAX = 100;
          int exchangeCost[MAX]; // 교환값
  • WinAPI/2011년스터디 . . . . 2 matches
         ||WS_MAXMIZE||9.최대화 된 상태로 윈도우 생성 ||
         ||WS_MAXMIZEBOX||20.최대화 버튼 ||
  • whiteblue/자료구조다항식구하기 . . . . 2 matches
         #define MAX 10000;
          int preExpon = MAX;
  • zennith/source . . . . 2 matches
         #define MAX_PRIME 50000
          for (i = 3; i < MAX_PRIME; i += 2) {
  • 데블스캠프2013/셋째날/머신러닝 . . . . 2 matches
         #define INT_MAX 0x7fffffff;
          int min = INT_MAX;
  • 몸짱프로젝트/CrossReference . . . . 2 matches
         const int MAX_LEN = 20;
         char word[MAX_LEN];
  • 토이/숫자뒤집기/김남훈 . . . . 2 matches
         const int MAX_BUF = 10;
          char input[MAX_BUF];
  • 3 N+1 Problem/조동영 . . . . 1 match
          int maxCount = 0;
          if(count > maxCount)
          maxCount = count;
          return maxCount;
          cout << "MAX cycle-length값은 " << CheckCount(num1,num2) << "입니다." << endl;
  • 5인용C++스터디/에디트박스와콤보박스 . . . . 1 match
         EN_MAXTEXT / 지정한 문자열 길이를 초과하였다.
  • AustralianVoting/Leonardong . . . . 1 match
          int result = INT_MAX;
  • CuttingSticks/김상섭 . . . . 1 match
          int temp1,min = INT_MAX;
  • HanoiTowerTroublesAgain!/황재선 . . . . 1 match
          public int maxBall(int numOfPeg) {
          if (ballNumber == Integer.MAX_VALUE) {
          int numOfBall = hanoi.maxBall(numOfPeg);
  • ProjectPrometheus/LibraryCgiAnalysis . . . . 1 match
          #'maxdisp': '10',
         http://165.194.100.2/cgi-bin/mcu201?LIBRCODE=ATSL&USERID=abracadabra&SYSDB=R&HISNO=0010&SEQNO=21&MAXDISP=10
  • Refactoring/ComposingMethods . . . . 1 match
          final boolean isMacOs = platform.toUpperCase().indexOf("MAX") > -1;
          if ( isMaxOs && isIEBrowser && wasResized ) {
  • WinampPluginProgramming/DSP . . . . 1 match
          SendDlgItemMessage(hwndDlg,IDC_SLIDER1,TBM_SETRANGEMAX,0,18);
  • [Lovely]boy^_^/Diary/8/6_8/10 . . . . 1 match
         || 3D || 3D MAX로 개체 읽어와서 GL에서 그리기 || || 세미나 받음 ||
  • 만년달력/강희경,Leonardong . . . . 1 match
          if ( year <= 0 || year >INT_MAX || month <=0 || month>12)
  • 상협/Diary/8월 . . . . 1 match
         || ["3DGraphicsFoundation"] || 3D MAX ASE 파일 OpenGL에서 읽기 || 2% || 흑... -_-;;||
  • 정모/2012.4.30 . . . . 1 match
          wibro는 WiMAX 프로토콜을 이용한 상표명입니다. wibro의 경우 IEEE 802.16e 표준을
  • 프로그래밍은습관이다 . . . . 1 match
          * 저번에 [상규]형이 for(i=0; i<MAX; i++){...}이런식의 아주 작은 패턴이라고 말할수 있는것을 무엇이라고 설명해 주셨었는데 정확하게 용어가 생각이 안나네요;; - [톱아보다]
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