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AnEasyProblem/정진경 (rev. 1.11)

An Easy Problem/정진경

Describe AnEasyProblem/정진경 here

Source Code

main(n,a,b){for(;a=b=scanf("%d",&n),n;printf("%d\n",n+a*b-b/2)){for(;a&~n;a*=2);for(;(b|a*b)&n;n+=b-a*b,b*=2);}}

// 164K 0MS C 112B


(define (mod a b)
  (if (< a b)
      a
      (mod(- a b) b)
      )
  )

(define (quot a b)
  (/ (- a (mod a b)) b)
  )

(define (BitCount n)
  (if (< n 1)
      0
      (+ (BitCount (quot n 2)) (mod n 2))
      )
  )

(define (SearchBitN n m)
  (if (= n (BitCount m))
      m
      (SearchBitN n (+ m 1))
      )
  )

(define (AnEasyProblem n)
  (SearchBitN (BitCount n) (+ n 1))
  )

...

  • 첫번째 제출에 상콤하게 Accept! 나름 열심히 줄여본다고 코드를 줄여봤지만. 역시 갈 길이 머네요... -정진경
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