Status ¶
| Problem | 2453 | User | jereneal20 |
| Memory | 388K | Time | 125MS |
| Language | GCC | Result | Accepted |
Idea ¶
- . 1 갯 for 구고, 1갯 까 1 계.
Source Code ¶
#include <stdio.h>
int bincount(int X);
int main()
{
int N,n,k=0;
while(1){
scanf("%d",&N);
if(N==0) break;
k=bincount(N);
for(n=N+1;k!=bincount(n);n++){}
printf("%d\n",n);
}
return 0;
}
int bincount(int X)
{
int nf,kf=0;
for(nf=X;nf>0;nf=nf>>1){
if(nf%2==1) kf++;
}
return kf;
}










