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최소정수의합/문보창

~cpp 
#include <iostream.h>

int find_min_sum(int bound_num) 
{ 
	int n = 1;
	while ((n * n + n) / 2 < bound_num) n++;
	return n;
}
		
inline void show_min_sum(int n) { cout << n << " " << (n * n + n) / 2 << endl; }

void main()
{
	show_min_sum(find_min_sum(3000));
}

한테 할


  • ? n(n+1)/2 n , ?
    ? -
  • ... 히 n(n+1)/2 . , 해 , ( ), , . --

- -> : , 해 ? ㅋ

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