#include <stdio.h>

int main () {
	int i, j, k;

	for (i = 0; i < 3; i++) {
		for (j = 0; j < 9; j++) {
			for (k = 0; k < 3; k++) {
				printf("%d * %d = %2d    ", (k + 1) + (i * 3), j + 1, ((k + 1) + (i * 3)) * (j + 1));
			}
			printf("\n");
		}
		printf("\n");
	}
	return 0;
}

//아직 9 8 7 5 는 구현이 되지 않았습니다.
짜다만 코드인데 저장할데가 없어서

#include<stdio.h>

int main(void){
    
    int n,m;
    int a;
    int b;
    int c;
  
    
    printf("n~m단\n");
    printf("m please : ");
    scanf("%d", &m);
    printf("n please : ");
    scanf("%d", &n);
    
    if(m-n == 0){
        printf("wrong input\n");
    }
    else if(m-n <=2){
        for(b=1; b<10; b++){
        
            for(a=n; a<=m ; a++){
                printf("%d x %d =  %2d     ", a, b, a*b      );
            }
        printf("\n");
    }
    }
    else if(m-n == 3){
        for(c=0;c<2;c++){
            for(b=1; b<10; b++){
        
                for(a=n; a<=n+1 ; a++){
                    printf("%d x %d =  %2d     ", (a+(c*2)), b, (a+(c*2))*b      );
                }
            printf("\n");
            }
            printf("\n");
        }    
    }
    else if(m-n == 4){
         for(c=0;c<2;c++){
            for(b=1; b<10; b++){
        
                for(a=n; a<=n+2 ; a++){
                    printf("%d x %d =  %2d     ", (a+(c*2)), b, (a+(c*2))*b      );
                }
            printf("\n");
            }
            printf("\n");
        }    
        
    }
    else if(m-n == 5){
        for(c=0;c<2;c++){
            for(b=1; b<10; b++){
        
                for(a=n; a<=n+2; a++){
                    printf("%d x %d =  %2d     ", (a+(c*3)), b, (a+(c*3))*b      );
                }
            printf("\n");
            }
            printf("\n");
        }    
    }
        
    
    
    
    return 0;
}